Boolean algebra - Converting DNF form to CNF form

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I´ve tried at least dozen ways to convert DNF to CNF, yet I always end up with something wrong. Here is the DNF: (B ∧ D) ∨ (C ∧ D) ∨ (¬D ∧ ¬B) ∨ (¬D ∧ ¬C) .

Is there someone who can help me with it ?

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