I had the following fact:
$A\subset X,f:A\to Y$ , where Y is Hausdorff space .f is continuous function on A. If there is continuous extension of f as $g:\bar A\to Y$ exist .Then this extension is unique.
I know that such extension need not exist .
I was thinking all assumption kept same and if we relaxed Hausdorff condition then the result must not hold.
I tried to find the counterexample.
I tried finite point non Hausdorff topology, But still not successful.I would be thankful if someone helps me to find such an example.
Thanks a lot
If $Y$ is the real line (or any set with more than one point) with indiscrete topology then any function into $Y$ is continuous. Obviously the extension is not unique in this case.