How do I find the counter example for...
If a function $g$ is differentiable at $a$ and a function $f$ is not differentiable at $g(a)$, then the function $f \circ g$ cannot be differentiable at $a$.
How do I find the counter example for...
If a function $g$ is differentiable at $a$ and a function $f$ is not differentiable at $g(a)$, then the function $f \circ g$ cannot be differentiable at $a$.
How about $f(x)=|x|$ and $g(x)=x^2$. $g$ is differentiable at $0$ but $f$ is not. On the other hand, $(f\circ g)(x)=x^2$.