Disproving Differentiable Functions with Counter Examples

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If a function $g$ is differentiable at $a$ and a function $f$ is not differentiable at $g(a)$, then the function $f \circ g$ cannot be differentiable at $a$.

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How about $f(x)=|x|$ and $g(x)=x^2$. $g$ is differentiable at $0$ but $f$ is not. On the other hand, $(f\circ g)(x)=x^2$.

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The trivial example: $g(x)=b$ and $f(x)=$'anything defined at $b$ with discontinuity at $b$'.