Dividing an angle into five equal parts by ruler and Compass Construction

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Things I know:
1. We can divide any angle into two
2. We can prove that $\pi/3$ can not be trisected. Thus trisection is not true in general.
3. A regular $n$-gon can only be constructed if and only if $\phi(n)=2^t$ for some integer $t$. Where $\phi(n)$ is the number of relatively prime numbers less than $n$ (Euler totient function)

I also went over this problem. But the thing that I don't understand is in those cases they talk about constructing a regular $n$-gon. That is we divide $360^{\circ}$ into $n$ equal parts. Which in my case will be $n=5$. But what I need is different.
I need to check whether any angle $\theta$ can be divided into $5$ equal parts.

Appreciate your help

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No, it is not possible to pentasect any angle using straightedge and compass. If it were possible to do so, then it would be possible to construct a regular $25$-gon. However this is impossible by the Gauss-Wantzel theorem, which implies that if an $n$-gon is constructible, then the odd prime factors of $n$ are distinct.

So in general for any $n$ that is not a power of two, there is no construction that divides any angle into $n$ equal parts, otherwise you could construct a $n^2$-gon.