I need to find the distance from the barycenter of an equilateral triangle to the edge in a given angle.
Here's a little sketch:

Given the outer radius of the triangle, the angle and the rotation (assuming the rotation in the picture would be $0$), I need to find the distance from the point on the edge (marked as red in the sketch) to the center.
Any help is appreciated!
This expression works for your particular choice of the angle: $$d=\frac{R}{2\cos(\arccos(\sin(3\alpha))/3)},$$ where $R$ is the radius of circumscribed circle (I assume this was meant by "outer radius of the triangle").