The prime number $$p=82\ 954\ 517$$ has the property that the numbers $$2!+p,3!+p,\cdots , 11!+p$$ are all prime, but $12!+p$ is composite. Upto $10^{10}$, the only other prime with this property is $105\ 204\ 557$
Does a prime $p$ exist such that $$2!+p,3!+p,\cdots , 12!+p$$ are all prime ? If yes, which is the smallest such prime ? Such a prime must exceed $10^{10}$
Update : The prime $$p=79\ 017\ 245\ 897$$ is even better than what I wanted. $j!+p$ is prime for $j=2,3,4,\cdots,13$. Now it remains to find the minimum primes for the limit $12$ and the limit $13$
I've only found the number you've found yourself as well:
I did this using an exhaustive search (I've calculated all the prime numbers up to 160,000,000,000 and then checked for each prime if the above sums are in the list). This also shows that 79,017,245,897 is the smallest prime with this property.
I'll repeat it now for factorials up to 12! and add it here as soon as it has finished. Will there be a maximum? I mean will there be a number $n$ such that there doesn't exist a prime $p$ for which $p + i!$ is prime for all $i \in \{2, \ldots, n\}$.
As promised, my results for $n = 12$:
IOW, 79,017,245,897 is the smallest both for $n = 12$ and $n = 13$.