What's your trouble at the end? $(-x)^n=(-1)^nx^n$, so you got $$\sum_{n=0}^{\infty}\left(2\cdot (-1)^n -1\right)x^n$$
Note the coefficients only depend on whether $n$ is even or odd.
In any event, it is possibly easier to do this as $$(1-3x)\cdot\frac{1}{1-x^2}=(1-3x)\left(1+x^2+x^4+\cdots\right)$$
What's your trouble at the end? $(-x)^n=(-1)^nx^n$, so you got $$\sum_{n=0}^{\infty}\left(2\cdot (-1)^n -1\right)x^n$$ Note the coefficients only depend on whether $n$ is even or odd.
In any event, it is possibly easier to do this as $$(1-3x)\cdot\frac{1}{1-x^2}=(1-3x)\left(1+x^2+x^4+\cdots\right)$$