How can de Rham cohomology find obstructions?

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A differential form is closed iff its exterior derivative is $0$.
A differential $k$-form $w$ is exact iff there exists a differential $(k-1)$-form $\eta$ so that $\hbox{d}\eta = \omega$.

Every exact differential form is closed, but closed differential forms are only locally exact (Poincare's lemma).

The quotient of closed $k$-forms modulo exact $k$-forms is the $k$-th de Rham cohomology group $H_{\text{dR}}^k(M)$ for some manifold $M$.

What's an example of an obstruction that de Rham cohomology can help identify (and how does it identify it)?

(Possible examples: global integrability of $k$-forms, existence and integrability of vectors fields, existence of circle bundles, existence of fiber bundles, existence of global sections, existence of connections, etc.)

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There are lots of examples, the one I've thought comes from symplectic geometry.

Let $M$ be a compact smooth manifold, a 2-form $\omega \in \Omega^2(M)$ is symplectic if it is non-degenerate (so if $\iota_X\omega$ is not the zero form unless $X = 0$) and closed. A symplectic manifold is a pair $(M,\omega)$.

The existence of such a non-degenerate form forces $M$ to be even-dimensional, say $\operatorname{dim}M = 2n$, one can check that non-degeneracy implies that $\omega^n$ is a volume form; in particular it can't be exact. Thus $[\omega]\neq 0$. Reading this reasoning backwards, we find that, if $H_{DR}^2(M) = 0$, then $M$ cannot be symplectic.