I have a simple equation where:
- $f(x) = 1-e^{-x/a}$
- $g(x) = e^{-x/d}$
- $h(x) = f(x)g(x)$
This looks like this:
https://www.desmos.com/calculator/gquxkhxqci
I would like $h(x)$ to automatically scale to a max height of hitting $y=1$.
I note that it is possible to adjust the height of $h(x)$ by rewriting $g(x) = e^{h-x/d}$, where $h$ is a height constant. Could $h$ be automatically calculated or some other scaling method used to maintain a max of $y=1$?
Essentially I think I need a way of finding the $x$-value of $h(x)$ where $h(x)$ reaches its maximum $y$-level (ie. derivative = 0). Then I can divide $h(x)$ by this max $y$-level to scale it to that maximum.
How can this be done?
Thanks.

Never mind. I solved it with some help from Wolfram Alpha:
https://www.desmos.com/calculator/fvkz8o95pa