How can I derive $\cos s = \cos x \cdot \cos y$ from the spherical triangle?

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I had read that for a "spherical" triangle i.e. all sides are equal and all angles are 90 degrees if e.g.
enter image description here

(I am sorry for the crude diagram, didn't know how to make it better)

it is: $\cos s = \cos x \cdot \cos y$

but I am not sure how we come about this.
I think:
$x = s \cdot \cos y$ and $y = s \cdot cos x$ and I assume that we can treat each side as hypotenuse but I can't derive the formula.
I remember that if $x$ and $y$ are very small and we use the series definition for $sin$ and $cos$ and ignoring all $x^2$ and rest terms as very small, we can get $s^2 = x^2 + y^2$ which is the pythagorean theorem.

Is there some way to derive $\cos s = \cos x \cdot \cos y$ from the triangle that I am missing?