Is Projective Geometric Algebra a strict subset of Conformal Geometric Algebra?

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My understanding is that CGA has an additional basis vector $e_{\infty}$, so it would seem to me that if that is the only difference then PGA fits entirely within CGA.

However I don't know if the introduction of the new basis affects some of the operations, since now the pesudoscalar of PGA is not a pseudoscalar in CGA, since there are 5 grade 4 blades.