Laurent series of algebraic function

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Consider function

$$f(z)=\frac{1}{\sqrt{a^2-z^2}+b\sqrt{c^2-z^2}}.$$

It has pole

$$z = \frac{\sqrt{b^2 c^2 - a^2}}{\sqrt{b^2-1}}$$.

I wanna find Laurent series of $f$ around singular point.

For $b=1$, I put $f$ in partial fraction to proced.

How to find Laurent series for $b \ne 1$?

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Hint: $$ \frac{1}{\sqrt{a^2-z^2}+b\sqrt{c^2-z^2}}=\frac{\sqrt{a^2-z^2}-b\sqrt{c^2-z^2}}{a^2-z^2-b^2(c^2-z^2)}=\frac{\sqrt{a^2-z_0^2-(z^2-z_0^2)}-b\sqrt{c^2-z_0^2-(z^2-z_0^2)}}{(b^2-1)(z^2-z_0^2)}, $$ where $$ z_0 = \frac{\sqrt{b^2 c^2 - a^2}}{\sqrt{b^2-1}}. $$