Consider the function
$$f(x)=-2\log(x-10)$$
How can I obtain its graph from transforming the function
$$g(x)=10^x\text{ ?}$$
I guess with $\log$ they mean the logarithm to base $10$. So what I tried to do is
$$10^{-2}\cdot(x-10)=g(f(x))$$
So I would first shift graph of $id(x)=x$ to the right by $10$ and then adjust its slope by $10^{-2}$ ?
Finally I take the logarithm of that?
Recognize that $$g(x)=10^x\iff g^{-1}(x)=\log x$$ and as such, we can write $$f(x)=-2g^{-1}(x-10).$$
Therefore, from the graph of $g(x)$, to get $f(x)$ we can perform the following operations in order: