Given that
$$P(A \cup B) = P(A) + P(B) - P(A\cap B)$$
would it also thus be accurate to say that
$$P(A \cup B^C) = P(A) + P(B^C) - P(A\cap B^C)$$
Given that
$$P(A \cup B) = P(A) + P(B) - P(A\cap B)$$
would it also thus be accurate to say that
$$P(A \cup B^C) = P(A) + P(B^C) - P(A\cap B^C)$$
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