Simple shape rotation

4.6k Views Asked by At

I feel like an idiot for asking, I got this question in a practice paper, it's the first question so it's easy. enter image description here

The question is "describe fully the single transformation that will map shape $P$ onto shape $Q$"

To me this is simply "Rotation $180^o$ about the point $(0, 1)$" However the mark scheme thinks it is $90^o$ clockwise?

Is there any way this could be true, it's not the first mistake in the mark scheme, but I need to be sure for my exam. (sorry if this question is to basic for here)

2

There are 2 best solutions below

2
On BEST ANSWER

I assume that by "transformation" they mean "isometry" (else there would be infinitely many different transformations mapping these shapes onto each other).

The mark scheme is right; this is a rotation through $90^\circ$ clockwise, but about the point $(-2,3)$, not $(0,1)$. My grasp of what may have made you think it's $180^\circ$ is probably insufficient for me to say anything helpful about that, but in case you were focussing on the points at $(1,2)$ and $(-1,0)$, which are indeed related by a rotation through $180^\circ$ about $(0,1)$, note a) that these don't correspond to each other in the shapes and b) that no other pairs of points are related by this rotation.

1
On

Your mark scheme seems to be correct. Look at the small line segment (1,4)-(2,4) in the polygon. It maps to the vertical segment (-1,0)-(-1,1).