What do you mean by "coordinate transformation of differential operators" , after all?

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Let $\varphi (u,v,w)$ be a orthogonal coordinate transformation from the $u,v,w$ coordinate system to the $x,y,$z coordinate system.
Let $\mathbf{F}(x,y,z)$ be a vector field defined in $x,y,z$ space, and $f(x,y,z)$ be a scalar field defined in $x,y,z$ space.
Let $\xi$ be a differential operator acting on a function or vector field defined in x,y,z space.
(i.e, The $\xi$ is a differential operator that can act on $\mathbf{F}(x,y,z)$ or $f$ above)

My question.

Am I right if I understand that a coordinate transformation by $\varphi$ of a differential operator $\xi$ is to find $\xi '$ such that;

  1. $\xi'$ is a differential operator acting on a function or vector field defined in $u,v,w$ space.
  2. $\xi'$ satisfies
    $\xi\left[f\right]\left(\varphi\left(u,v,w\right)\right)=\left(\xi^\prime\left[\varphi^{*}f\right]\right)\left(u,v,w\right) $ (for scalar field $f(x,y,z)$)
    $\xi\left[\mathbf{F}\right]\left(\varphi\left(u,v,w\right)\right)=\left(\xi^\prime\left[\varphi^{*}\mathbf{F}\right]\right)\left(u,v,w\right) $ (for vector field $\mathbf{F}(x,y,z)$)

    Here,
  • $\varphi^{*}f := f\circ \varphi$,
  • $\varphi^{*}\mathbf{F}= F_u \mathbf{t}_u + F_v \mathbf{t}_v + F_w \mathbf{t}_w$ ,
    $\mathbf{t}_u(u,v,w):= \frac{1}{h_u(u,v,w)}\frac{\partial \varphi}{\partial u}(u,v,w) ,\cdots ,$
    $h_u(u,v,w):=\left\|\frac{\partial \varphi}{\partial u}(u,v,w)\right\| , \cdots ,$
    $ F_u(u,v,w):= <\mathbf{F}\circ\varphi (u,v,w)|\mathbf{t}_u(u,v,w)> ,\cdots ,$

Where

  • $< | >$ represents inner product ,
  • $\left\| \right\|$ represents norm ,
  • $\xi\left[f\right]\left(\varphi\left(u,v,w\right)\right)$ is the value of at $\varphi\left(u,v,w\right)$ of $\xi\left[f\right]$, $\xi\left[f\right]$ is what $\xi$ acts on $f$. (The same manner for vector fields.)
  • $\cdots$