In this situation, the chances of having a boy/girl is NOT equally likely. The probability of having a boy is 0.55, so how does this knowledge change how I approach the problem>
I've tried it by doing (0.55)^4 * (0.45) / 32 to be a solution, but also 5C4/32 but both wield different answers. So, I'm not sure I understand how I'm supposed to get to the proper answer.
If $P(B)=0.55$, $P(G)=1-0.55=0.45$
$$P(4 \text{boys and} 1 \text{girl})=\binom{5}{4}\times (0.55)^4\times (0.45)^1$$