Am I finding curl correct?

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I have a field $E(x,y)=2xi+yj$, and want to find the curl. I do this by the next way:

$rotE=i\dfrac{d(2x+y)}{dx}+j\dfrac{d(2x+y)}{dy}$ and get $2i+j$

Is it correct?

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No it's wrong. We have $$\nabla\times E=(\dfrac{\partial}{\partial x}i+\dfrac{\partial}{\partial y}j)\times E=\dfrac{\partial y}{\partial x}k-\dfrac{\partial 2x}{\partial y}k=0$$

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The $2$-dimensional curl is $\operatorname {rot} E=\frac{\partial (y)}{\partial x}-\frac{\partial (2x)}{\partial y}=0$.