Can I say that every integrable function is measurable?

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Let $(X, \mathcal S, \mu)$ be a measure space. Let $\Bbb L$ be the collection of all $\mathcal S$-measurable functions and let $L_1(\mu)$ be the collection of all $\mu$-integrable functions i.e. the collection of all the functions $f : X \longrightarrow \Bbb R^*$ such that $\int f^+\ d\mu < +\infty$ and $\int f^-\ d\mu < +\infty,$ where $f^+$ and $f^-$ respectively denote the positive part and the negative part of the function $f.$ Now suppose that $f \in L_1(\mu).$ Can we say that $f \in \Bbb L?$ What I know is that if $f \in \Bbb L$ and $\int f^+\ d\mu, \int f^-\ d\mu < +\infty$ then $f \in L_1(\mu).$ Is the converse true?

Any help in this regard will be highly appreciated. Thanks in advance.

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Yes. Remember how the integral was defines. First for simple and of course measurable functions. measurability is necessary here or course. Then, for positive (measurable) functions, you basically construct a sequence of simple measurable functions using preimages of the positive functions. This is where -maybe silently- the measurability condition is used.