Two points on the graph of $y=kx^p$ are labeled $A$ and $C$. Point $A$ has coordinates $(a,b)$, where $0<a<1$ and point $C$ has coordinates $(c,d)$, where
$1<c$.
If we are told that that the product
$k\cdot p$ is negative, what can be concluded about the points $A$ and $C$?
Defend your answer.
I can't figure this out. I have tried multiple times. The hint in the book that I have to prove y is decreasing so I figured then $a<b$ and $c>d$. How would I prove this.
Note that $y' = kpx^{p-1}$ so, for $x > 0$, $y'< 0$.
Therefore $y$ is decreasing for $x > 0$.
Since $0 < a < 1 < c$, $y$ is decreasing at both $A$ and $C$.
Since $a < 1 < c$, $A$ is to the left of $C$. Since $y$ is decreasing, $A$ is above $C$.