If $g(x,y)$ is continuous at $(x,y)$, is it always possible to find $f(x+y)$ such that $g = af$ with $a$ being real?

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Is true that for any continuous function $g$ at $(x,y)$, there exists a function $f(x+y)$ such that

$$g(x,y)=a f(x+y)$$

with $a$ being a real scalar?

In other words, is it always possible to find a function $f$ (having only one argument $=x+y$) and it represents another function $g$ (which has two arguments $x$ and $y$) up to a scalar multiple?

I am not sure if it is always possible, sometimes possible, or never possible. Also I am not sure if this is a kind of translation.

For example, if $g(x,y)=x^2+xy+y^2$, what should be $a$ and $f$?


Your help would be really appreciated. THANKS!