In the exterior of the ABCD square we construct the rhombus BCMN with BCM angle obtuse.How can i prove that A-C-M are collinear points?

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In the exterior of the ABCD square we construct the rhombus BCMN with BCM angle obtuse.Prove that A-C-M are collinear points

i need that result to another geometry problem and i don't have many ideas how can i proof that.

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You can't because it's wrong. Take $\measuredangle BCM=100^{\circ}.$