I am trying to understand the difference between the following two equations:
$$\bar{P} = \limsup_{t \to \infty}\frac{1}{t} \sum_{\tau = 0}^{t-1}E\{P[\tau]\} < \infty$$ and $$\bar{P} = \lim_{t \to \infty}\frac{1}{t} \sum_{\tau = 0}^{t-1}E\{P[\tau]\} < \infty$$
where $\bar{P}$ denotes the average value of P and E stands for expectation. I have previously come across equations like the second one but I am not able to understand when to use equations of the first type. I have read the definition on Wikipedia's Supremum page but I am failing to understand the intuitive meaning of when to use what. The wiki defines it as:
A set A of real numbers (shown as blue balls), a set of upper bounds of A (red balls), and the smallest such upper bound, that is, the supremum of A (shown as a red diamond).
What does a set of upper bounds actually mean? I thought upper bound means the uppermost value but I guess my understanding is flawed. Can someone please tell me the difference between the two and give me some easy to understand example to understand the difference between a normal limit and supremum limit?
I think your question is about the difference between limit, limsup and sup? I will illustrate the differences with an example. Let's consider the sequence: $$3, 4, -7, 2, 1, 7, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, \dots$$ (The ellipsis indicates that the terms alternate $+1$ and $-1$ forever after the terms I have given explicitly.)
The least upper bound (sup) of this set is $7$ [EDIT: thanks Sivaram]. This is the smallest real number that bounds every term from above. The sequence has no limit. However, the $\limsup$ is $1$.
The formal definition of $\limsup$ is that for each $N$, you consider the "tail" of the sequence, starting at the $N^\text{th}$ position. You take the sup of this tail. Now, take the limit as $N \rightarrow \infty$. This limit exists because the sequences of sup is monotone. (We also allow a limit of $\pm \infty$ so monotonicity suffices.)
Note that if the limit of the $a_n$ exists, then we have $$ \lim a_n = \limsup a_n.$$ This means that in "nice" examples, your two definitions of $\bar P$ are the same. It's only in cases with lots of oscillations that $\lim a_n$ doesn't exist, and you will want to use $\limsup a_n$.