The problem is: 95 people participated in an experiment. $N$ people were given food with an enzyme in it to help people lose weight. However, some people have gained an illness from eating the food with enzymes in it. It is stated that the probability of a person developing the illness can increase from $0.1$ with normal food to $0.5$ with the enzyme.
i) what is the probability, if the person has an illness, to have eaten the food with the enzyme?
ii) What is the maximum N so that the probability in i) is less than 0.65
I assume that the information given is that total is 95 $$ P(\text{illness} \mid \text{normal}) = 0.1 $$ $$ P(\text{illness} \mid \text{enzyme}) = 0.5 $$
I believe in part i) I need to use Bayes' Theorem so I do this:
$$ P(\text{enzyme} \mid \text{illness}) = \frac{P(\text{illness} \mid \text{enzyme}) \times P(\text{enzyme})}{P(\text{illness})}, $$
but I am not sure how to get the other probabilities to work that out. I could really use the help
$P(\text{enzyme})$ is N/95 and N is something to be adjusted.
For $P(\text{illness})$ you use the very useful breakdown for the denominator in Bayes' theorem $P(B)=P(B\mid A)~P(A) + P(B\mid \overline A)~(1-P(A))$, here $$P(\text{illness}\mid \text{enzyme})~P(\text{enzyme})+P(\text{illness}\mid\text{normal})~(1-P(\text{enzyme}))$$