Solving $\Pi^t_i 2 m_i \left(N_i!\right)^{m_i} $

Question

I would like to work out the result of $\Pi^t_i 2 m_i \left(N_i!\right)^{m_i} $.

Here, $t, i, N_i, m_i$ are positive integers.

My effort:

$$ \Pi^t_i 2 m_i \left(N_i!\right)^{m_i} \implies (2 m_1 \left(N_1!\right)^{m_1}) (2 m_2 \left(N_2!\right)^{m_2}) \ldots (2 m_t \left(N_t!\right)^{m_t}) $$

I do not know how to proceed from here. Is there any shortcut?