I am solving the following problem:
Let $f(x) =\sqrt{x}$. Find a formula for a function $g$ whose graph is obtained from $f$ from the given sequence of transformations:
- shift right $3$ units
- horizontal shrink by a factor of $2$
- shift up $1$ unit
I think that$ g(x) = f(2(x-3)) + 1 = \sqrt{2x-6} + 1$, but in the answers it says $\sqrt{2x-3} + 1$, so i assume $g(x) = f(2x-3) +1$, but wouldn't that mean that the horizontal shrink was done first and afterwards the right horizontal shift?
When we do a horizontal shrink by a factor of $b$ we replace $x$ with $bx$, rather than multiplying the whole expression by b. So:
$$g(x) = f(2x-3) + 1$$
not:
$$g(x) = f(2(x-3)) + 1$$